Answer :
Final answer:
The cheetah's initial velocity was 36.9 ft/sec, and it traveled approximately 61.5 ft in 1.25 seconds.
Explanation:
To find the cheetah's initial velocity, we can use the formula:
v = u + at
Where:
v is the final velocity (39.4 ft/sec)u is the initial velocity (unknown)a is the acceleration (2.10 ft/sec²)t is the time taken (1.25 seconds)Substituting the given values into the formula, we get:
39.4 = u + 2.10 × 1.25
Solving for u, we find:
u = 36.9 ft/sec
To find the distance traveled by the cheetah, we can use the formula:
s = ut + 0.5at²
Substituting the given values into the formula, we get:
s = 36.9 × 1.25 + 0.5 × 2.10 × (1.25)²
s ≈ 61.5 ft