High School

Calculate the specific heat (J/g∘C) ( J / g ∘ C ) for a 25.5 g g sample of a metal that absorbs 663 J J when temperature increases from 36.6 ∘C ∘ C to98.4 ∘C ∘ C .

Answer :

The specific heat of the metal is approximately 0.45 J/g°C.

To calculate the specific heat of the metal, we can use the formula

Q = mcΔT,

where Q is the heat energy absorbed, m is the mass of the sample, c is the specific heat, and ΔT is the change in temperature.

Rearranging the formula, we get c = Q/(mΔT).

Plugging in the values from the question,

c = 663 J / (25.5 g * (98.4 °C - 36.6 °C)).

Calculating the expression gives us a specific heat of approximately 0.45 J/g°C.

Learn more about Specific heat here:

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