High School

A 25.0 mL solution of [tex]Ba(OH)_2[/tex] is neutralized with 36.6 mL of 0.250 M [tex]HBr[/tex]. What is the concentration of the original [tex]Ba(OH)_2[/tex] solution?

Answer :

Final answer:

The concentration of the original Ba(OH)2 solution can be calculated using the given information and the formula for concentration. The concentration is approximately 0.292 M.

Explanation:

To calculate the concentration of the original Ba(OH)2 solution, we can follow these steps:

  • Write the balanced chemical equation for the reaction between Ba(OH)2 and HBr:

Ba(OH)2 + 2HBr → BaBr2 + 2H2O

  • Use the balanced equation to determine the mole ratio between Ba(OH)2 and HBr. In this case, the ratio is 1:2.
  • Calculate the moles of HBr using its concentration and volume:

Moles of HBr = (concentration of HBr) × (volume of HBr solution in liters)

  • Use the mole ratio to calculate the moles of Ba(OH)2:

Moles of Ba(OH)2 = (moles of HBr) / 2

  • Finally, calculate the concentration of the Ba(OH)2 solution:

Concentration of Ba(OH)2 = (moles of Ba(OH)2) / (volume of Ba(OH)2 solution in liters)

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