High School

Determine the temperature of a reaction if K = 1.2 x 10-6 when AG° = +36.9 kJ/mol.

Answer :

The temperature of a reaction can be determined using the Gibbs free energy equation, which states that

ΔG° = -RTlnK,

where ΔG° is the standard free energy change of the reaction,

R is the gas constant,

T is the temperature in Kelvin, and

K is the equilibrium constant.

By rearranging the equation, we can solve for the temperature (T) as T = -ΔG°/ (RlnK).



In this problem, we are given that K = 1.2 x 10^-6 and ΔG° = +36.9 kJ/mol. We can substitute these values into the equation and solve for the temperature as:


T = -(+36.9 kJ/mol) / (8.314 J/mol K * ln(1.2 x 10^-6))


T = 548.7 K or 275.7°C


Therefore, the temperature of the reaction is approximately 275.7°C if K = 1.2 x 10^-6 when ΔG° = +36.9 kJ/mol.

If the temperature is changed, the value of K will also change, indicating whether the reaction will favor the formation of products or reactants at the new temperature.

To know more about Gibbs free energy here

https://brainly.com/question/20358734

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