College

A balloon is filled with 36.6 liters of helium gas. What is the mass of the helium at STP?

- [?] grams He
- 1 mole = 22.4 L of gas at STP

Report your answer with the appropriate number of significant figures.

Answer :

Final answer:

To find the mass of helium at STP, divide the given volume of helium gas by the molar volume of gas at STP, then multiply by the molar mass of helium gas.


Explanation:

To find the mass of helium at STP, we need to convert the given volume of helium gas to moles using the molar volume of gas at STP. The molar volume of a gas at STP is 22.4 L/mol. First, convert 36.6 liters to moles by dividing the volume by the molar volume:




  1. 36.6 L ÷ 22.4 L/mol = 1.63 moles



Next, we can use the molar mass of helium to convert moles to grams. The molar mass of helium is approximately 4 g/mol. Multiply the number of moles by the molar mass:




  1. 1.63 moles × 4 g/mol = 6.52 grams



Therefore, the mass of helium at STP is 6.52 grams (rounded to three significant figures).


Learn more about Mass calculation of helium at STP here:

https://brainly.com/question/40665096


Other Questions