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What is the volume of 1.758 moles of a gas at standard temperature and pressure?

A. 0.0401 L
B. 19.7 L
C. 22.4 L
D. 39.4 L

Answer :

To find the volume of 1.758 moles of a gas at standard temperature and pressure (STP), let's follow these steps:

1. Understand STP conditions: Under standard temperature and pressure conditions, one mole of an ideal gas occupies 22.4 liters.

2. Identify the information given: We know we have 1.758 moles of gas.

3. Use the volume of one mole at STP: Since each mole of gas occupies 22.4 liters at STP, we can multiply the number of moles by the volume per mole.

4. Calculate the total volume:
[tex]\[
\text{Volume} = \text{Number of moles} \times \text{Volume per mole}
\][/tex]
[tex]\[
\text{Volume} = 1.758 \, \text{moles} \times 22.4 \, \text{L/mole}
\][/tex]

5. Compute the result: Performing the multiplication gives us a volume of approximately 39.3792 liters.

Therefore, the volume of 1.758 moles of a gas at standard temperature and pressure is approximately 39.4 liters. So, the correct answer is option d. 39.4 L.

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