Answer :
Final answer:
To find the new pressure when the temperature is changed from 402 K to 251 K, we can use Gay-Lussac's Law. The new pressure will be approximately 61.3 kPa.
Explanation:
When a sealed plastic syringe undergoes a change in temperature, its pressure also changes. In this case, the original pressure is 97.8 kPa at a temperature of 402 K.
To find the new pressure when the temperature is 251 K, we can use Gay-Lussac's Law.
Gay-Lussac's Law states that the pressure of a gas is directly proportional to its temperature, as long as the volume and amount of gas are constant.
We can use the formula P₁/T₁ = P₂/T₂, where P₁ and T₁ are the initial pressure and temperature, and P₂ and T₂ are the final pressure and temperature.
Plugging in the given values, we have 97.8 kPa / 402 K = P₂ / 251 K.
Solving for P₂, we get P₂ = (251 K * 97.8 kPa) / 402 K ≈ 61.3 kPa.
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