High School

Calculate and report the energy released by 1 mole of gasoline and the energy released by 1 mole of diesel in units of kJ. Assume a molecular weight (MW) of 100.2 g/mol for gasoline and 198.1 g/mol for diesel.

Given the lower heating value in MJ/kg:
- Gasoline: 43.4 MJ/kg
- Diesel: 42.6 MJ/kg

Answer :

Final answer:

The energy released by one mole of gasoline is 4350.84 kJ, and one mole of diesel is 8437.86 kJ, based on their Lower Heating Values and molecular weights.

Explanation:

To calculate the energy released by one mole of gasoline and one mole of diesel, we use the given Lower Heating Values (LHV) expressed in megajoules per kilogram (MJ/kg) and the molecular weights (MW) provided.

First, we convert the LHV of gasoline and diesel from MJ/kg to kJ/g:

  • Gasoline: 43.4 MJ/kg = 43.4 imes 1000 kJ/kg = 43.4 kJ/g
  • Diesel: 42.6 MJ/kg = 42.6 imes 1000 kJ/kg = 42.6 kJ/g

Next, we calculate the energy per mole:

  • Gasoline: (43.4 kJ/g) imes (100.2 g/mol) = 4350.84 kJ/mol
  • Diesel: (42.6 kJ/g) imes (198.1 g/mol) = 8437.86 kJ/mol

Therefore, the energy released by one mole of gasoline is 4350.84 kJ and by one mole of diesel is 8437.86 kJ.

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