Answer :
Final answer:
The volume that 35.9 g of hydrogen gas will occupy at STP is approximately 804 L.
Explanation:
To find the volume of hydrogen gas at STP, we can use the ideal gas law.
The ideal gas law is PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
At STP (standard temperature and pressure), the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (K).
We can rearrange the ideal gas law to solve for volume: V = nRT/P.
To find the number of moles of hydrogen gas, we can use the molar mass of hydrogen (H₂), which is 2 grams per mole (g/mol).
Given that we have 35.9 grams of hydrogen gas, we can calculate the number of moles using the formula: moles = mass/molar mass. Therefore, the number of moles of hydrogen gas is 35.9 g / 2 g/mol = 17.95 moles.
Now we can substitute the values into the volume formula: V = (17.95 moles * 0.0821 L·atm/(mol·K) * 273.15 K) / 1 atm. Calculating this gives us a volume of approximately 804 L.
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