High School

A projectile is fired with an initial speed of 36.6 m/s at an angle of 42.2° above the horizontal on a long, flat firing range. What is the speed at the apex of the trajectory?

Answer :

Final answer:

The speed at the apex of the trajectory is 36.6 m/s.

Explanation:

To find the speed at the apex of the trajectory, we can consider the projectile motion as two separate motions - horizontal and vertical. The horizontal motion is constant, so the projectile's speed at the apex will be the same as its initial speed - 36.6 m/s.

The vertical motion can be analyzed using the equations of motion. The time taken by the projectile to reach the apex can be found using the formula t = u * sin(theta) / g, where u is the initial speed and theta is the angle of projection. The vertical component of the projectile's velocity at the apex can be found using the formula v = u * sin(theta) - g * t.

Therefore, the speed at the apex of the trajectory is 36.6 m/s.

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