High School

A sample of nickel is heated to 99.8 °C and placed in a coffee-cup calorimeter containing 150.0 g of water at 23.5 °C. After the metal cools, the final temperature of the metal and water mixture is 25.0 °C. If the specific heat capacity of nickel is 0.444 J/g°C and that of water is 4.184 J/g°C, what mass of nickel was originally heated? Assume no heat loss to the surroundings or to the calorimeter.

Answer :

Final answer:

The mass of the nickel originally heated is calculated using the principle of conservation of energy and the specific heat capacities of nickel and water. The equation used is Q = m * c * ∆T. The calculation yields a mass of 1,582 g for the nickel.

Explanation:

To find the mass of the nickel originally heated, we can use the principle of conservation of energy. The heat lost by the nickel is equal to the heat gained by the water in the calorimeter. We can calculate the heat lost by the nickel using the equation:

Q = m * c * ∆T

Where Q is the heat lost, m is the mass of the nickel, c is the specific heat capacity of nickel, and ∆T is the change in temperature of the nickel. We can then set this equal to the heat gained by the water:

Q = m_water * c_water * ∆T_water

Where m_water is the mass of the water, c_water is the specific heat capacity of water, and ∆T_water is the change in temperature of the water.

Since the final temperature of the mixture is 25.0 °C, the change in temperature for both the nickel and water is 25.0 °C - 99.8 °C = -74.8 °C.

Plugging in the values we know:

m * 0.444 J/g°C * -74.8 °C = 150.0 g * 4.184 J/g°C * -74.8 °C

Simplifying the equation, we can solve for m:

m = (150.0 g * 4.184 J/g°C * -74.8 °C) / (0.444 J/g°C)

This gives us a mass of the nickel originally heated to be 1,582 g (rounded to the nearest gram).

Other Questions