College

Select the correct answer.

Points [tex]A[/tex] and [tex]B[/tex] lie on a circle centered at point [tex]O[/tex]. If [tex]OA = 5[/tex] and [tex]\frac{\text{length } \hat{AB}}{\text{circumference}} = \frac{1}{4}[/tex], what is the area of sector [tex]AOB[/tex]? Use the value [tex]\pi = 3.14[/tex], and choose the closest answer.

A. 19.6 square units
B. 39.3 square units
C. 7.85 square units
D. 15.7 square units

Answer :

To find the area of sector [tex]\( AOB \)[/tex] in the circle, let's go through the steps to solve the problem:

1. Identify the Given Information:
- The circle is centered at point [tex]\( O \)[/tex].
- Radius [tex]\( OA = 5 \)[/tex] units.
- Arc [tex]\( \hat{AB} \)[/tex] is [tex]\(\frac{1}{4}\)[/tex] of the circumference of the circle.

2. Calculate the Total Circumference of the Circle:

The formula for the circumference of a circle is:

[tex]\[
\text{Circumference} = 2 \pi r
\][/tex]

Substituting the given radius [tex]\( r = 5 \)[/tex]:

[tex]\[
\text{Circumference} = 2 \times 3.14 \times 5 = 31.4
\][/tex]

3. Determine the Fraction of the Circle:

We are given that arc [tex]\( \hat{AB} \)[/tex] is [tex]\(\frac{1}{4}\)[/tex] of the circumference. Therefore, the arc length also indicates the fraction of the circle that sector [tex]\( AOB \)[/tex] covers.

4. Calculate the Area of the Sector:

The formula for the area of a sector is:

[tex]\[
\text{Area of sector} = \left( \frac{\text{Arc Length}}{\text{Circumference}} \right) \times \pi r^2
\][/tex]

Given that [tex]\(\frac{\text{Arc Length}}{\text{Circumference}} = \frac{1}{4}\)[/tex], substitute the values into the formula:

[tex]\[
\text{Area of sector} = \frac{1}{4} \times 3.14 \times 5^2
\][/tex]

[tex]\[
\text{Area of sector} = \frac{1}{4} \times 3.14 \times 25
\][/tex]

[tex]\[
\text{Area of sector} = \frac{1}{4} \times 78.5
\][/tex]

[tex]\[
\text{Area of sector} = 19.625
\][/tex]

5. Choose the Closest Option:

From the provided choices, 19.6 square units is the closest to our calculated area of 19.625. Therefore, the area of sector [tex]\( AOB \)[/tex] is approximately 19.6 square units.

Thus, the correct answer is:
A. 19.6 square units

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