Answer :
The molarity of the H2SO4 solution is 0.1245 M.
A solution of H2SO4 is neutralized by a 0.163 M NaOH solution when 38.2 mL of NaOH solution are added to a 25.0 mL H2SO4 solution. The balanced chemical equation for the reaction is:H2SO4 + 2NaOH → Na2SO4 + 2H2OTo determine the molarity of H2SO4, you need to use the stoichiometry of the balanced chemical equation. The balanced equation shows that 2 moles of NaOH react with 1 mole of H2SO4.
Therefore, the number of moles of NaOH used in the reaction is: moles NaOH = Molarity × Volume = 0.163 M × 0.0382 L = 0.0062266 mol Since 2 moles of NaOH reacts with 1 mole of H2SO4, then the number of moles of H2SO4 in the solution is :moles H2SO4 = 0.0062266 mol ÷ 2 = 0.0031133 mol The molarity of the H2SO4 solution is then calculated as follows: Molarity = moles ÷ volume Molarity = 0.0031133 mol ÷ 0.0250 L = 0.1245 M
Therefore, the molarity of the H2SO4 solution is 0.1245 M.
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