High School

Consider the following reaction at equilibrium:

\[ \text{Fe}_3\text{O}_4(s) + \text{CO}(g) \rightleftharpoons 3 \text{FeO}(s) + \text{CO}_2(g) \]

\(\Delta H^\circ = +35.9 \, \text{kJ}\)

What effect will increasing the volume have on the system?

A. No effect will be observed.
B. The reaction will shift to the right in the direction of products.
C. The equilibrium constant will decrease.
D. The reaction will shift to the left in the direction of reactants.

Answer :

Increasing the volume will have no effect on the system.

The given reaction is Fe₃O₄(s) + CO(g) ⇌ 3FeO(s) + CO₂(g). The equilibrium of a reaction is determined by the balance between the forward and reverse reactions. When the volume of the system is increased, it affects the concentrations of the reactants and products.

In this case, increasing the volume will cause a decrease in the overall pressure of the system. According to Le Chatelier's principle, a change in pressure will lead to a shift in the equilibrium position in a way that opposes the change.

In the given reaction, there is an equal number of moles of gas on both sides of the equation. Therefore, changing the volume and subsequently the pressure will not affect the equilibrium position. The system will not shift in either direction to restore equilibrium.

Hence, increasing the volume will have no effect on the system. The equilibrium will remain unchanged, and the concentrations of the reactants and products will stay the same.

To know more about Le Chatelier's principle refer here:

https://brainly.com/question/31664161#

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