Answer :
Final answer:
The magnitude of the force acting on a spring with a spring constant of 300 N/m that is stretched 15.3cm is 45.9 N. The calculation is based on Hooke's law (F = km), with the spring displacement converted to meters.
Explanation:
The question asks for the magnitude of the force acting on a spring. From the details provided, the spring constant is stated to be 300 N/m, and the spring is stretched to a distance of 15.3 cm. In physics, Hooke's law describes the relationship between the force exerted on a spring and the distance it is stretched or compressed. It is usually expressed as F = kx, where F is the force, k is the spring constant, and x is the distance the spring is stretched or compressed.
Before we proceed, we need to convert the displacement of the spring from cm to m. 1 cm equals 0.01 m, so 15.3 cm converts to 0.153 m. Now we substitute the known values into the equation F = kx:
F = (300 N/m) * (0.153 m) = 45.9 N.
Thus, the magnitude of the force acting on the spring is 45.9 N, which corresponds to answer option d in your multiple-choice list. The key factor in this type of question is understanding Hooke's law and making sure that the units of measurement are consistent.
Learn more about Hooke's Law here:
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