High School

The amount of energy needed to heat 6.1 g of a substance from 50.0°C to 80.0°C is 36.6 J. What is the specific heat capacity of this sample?

Answer :

As a result, the material has a specific heat capacity of 0.20 J/g°C.

How do you define simple specific heat capacity?

Its specific heat capacity is the amount of heat energy required to raise the temperature of a unit mass of any substance or matter by one degree Celsius.

We can use the following formula to find the substance's specific heat capacity: Q = m * c * ΔT

where Q is the extra energy in joules, m is the substance's mass in grammes, c is its specific heat capacity in joules per gramme of temperature, and T is the temperature change in degrees Celsius.

When we substitute the specified values, we obtain:

36.6 J = (6.1 g) * c * (80.0°C - 50.0°C)

Simplifying and solving for c, we get:

c = 36.6 J / (6.1 g * 30.0°C)

c = 0.20 J/g°C

To know more about temperature visit:-

https://brainly.com/question/29072206

#SPJ1

Other Questions