Answer :
The required percentage of years with more than 42" of rain is 7.64% (option c).
Statistics from a college's climate center indicate that the city the college is in gets an average of 35.9" of rain each year, with a standard deviation of 4.3".
Let X be the amount of rain in the city each year and assume X follows Normal distribution. Here the mean is μ = 35.9 and the standard deviation is σ = 4.3. We need to find the percentage of years with more than 42" of rain.The probability that X is greater than 42 isP(X > 42)
First, we need to standardize 42 into a z-score using the formula
z = (x - μ)/σ
z = (42 - 35.9)/4.3
z = 1.43
Now, we need to find P(Z > 1.43) using a Standard Normal Table.P(Z > 1.43) = 0.0764Therefore, the percentage of years with more than 42" of rain is 0.0764 x 100% = 7.64%
Hence, option (C) is the correct answer.
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