Answer :
The molarity of the KCl solution is 0.497 M. The molarity of the C₂H₂O solution is 0.321 M. The molarity of the KI solution is 0.0021 M.
(a)
Mass of KCl = 33.2 g
The volume of solution = 0.895 L
the number of moles present in KCl is:
Molar mass of KCl = 39.10 g/mol + 35.45 g/mol
KCl molar mass = 74.55 g/mol
Number of moles of KCl = mass of KCl / molar mass of KCl
Number of moles of KCl = 33.2 g / 74.55 g/mol = 0.445 mol
The molarity of KCl is:
Molarity = number of moles of solute / total volume of solution
Molarity = 0.445 mol / 0.895 L
Molarity = 0.497 M
Therefore, we can infer that the molarity of the KCl solution is 0.497 M.
(b)
Mass of C₂H₂O = 61.3 g
The volume of the solution = 3.4 L
Molar mass of C₂H₂O solution = 2(12.01 g/mol) + 2(1.01 g/mol) + 16.00 g/mol
Molar mass of C₂H₂O solution = 56.03 g/mol
Total Number of moles of C₂H₂O = mass of C₂H₂O / molar mass of C₂H₂O
Total Number of moles of C₂H₂O = 61.3 g / 56.03 g/mol = 1.094 mol
The molarity of the solution is:
Molarity = number of moles of solute/volume of solution in liters
Molarity = 1.094 mol / 3.4 L = 0.321 M
The molarity of the C₂H₂O solution is 0.321 M.
(c)
Mass of KI = 38.2 mg
The volume of the solution = 112 mL
Molar mass of KI = 39.10 g/mol + 126.90 g/mol = 166.00 g/mol
Total number of moles of KI = mass of KI / molar mass of KI
Total number of moles of KI = 38.2 mg / 166.00 g/mol = 0.00230 mol
Here we need to convert the milliliters to liters.
Volume of solution = 112 mL ÷ 100 = 0.112 L
Now, we can calculate the molarity:
Molarity = number of moles of solute/volume of solution in liters
Molarity = 0.000230 mol / 0.112 L = 0.0021 M
The molarity of the KI solution is 0.0021 M.
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