High School

A solution is composed of 1.90 mol cyclohexane ([tex]P°_{\text{cy}} = 97.6 \text{ torr}[/tex]) and 2.90 mol acetone ([tex]P°_{\text{ac}} = 229.5 \text{ torr}[/tex]). What is the total vapor pressure ([tex]P_{\text{total}}[/tex]) above this solution?

Answer :

Final answer:

The total vapor pressure above the solution is 190.884 torr.

Explanation:

To find the total vapor pressure above the solution, we can use Raoult's law. According to Raoult's law, the vapor pressure of a component in a solution is equal to the product of its mole fraction in the solution and its vapor pressure in the pure state. In this case, we have two components: cyclohexane and acetone. The vapor pressure of cyclohexane is 97.6 torr and the vapor pressure of acetone is 229.5 torr. The mole fractions of cyclohexane and acetone are 1.90 mol / (1.90 mol + 2.90 mol) = 0.396 and 2.90 mol / (1.90 mol + 2.90 mol) = 0.604, respectively. Therefore, the total vapor pressure above the solution is 0.396 * 97.6 torr + 0.604 * 229.5 torr = 190.884 torr.

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