High School

A 4.22 mol sample of Ar has a pressure of 1.21 atm and a temperature of 34 °C. What is its volume?

A. 87.9 L
B. 79.8 L
C. 89.7 L
D. 97.8 L

Answer :

We can use the ideal gas law equation to get the volume of the sample:

PV = nRT

Where:

P = pressure (in atm)

V = volume (in liters)

n = number of moles

R = ideal gas constant (0.0821 L·atm/mol·K)

T = temperature (in Kelvin)

The temperature must first be converted from Celsius to Kelvin:

T(K) = T(°C) + 273.15

T(K) = 34 + 273.15 = 307.15 K

The values ​​can now be entered into the ideal gas law equation as follows:

1.21 atm * V = 4.22 mol * 0.0821 L·atm/mol·K * 307.15 K

Simplifying the equation:

V = (4.22 mol * 0.0821 L·atm/mol·K * 307.15 K) / 1.21 atm

V = 87.886 L

The volume is roughly 87.9 L, rounded to three significant numbers.

Therefore, the correct option is A.

Learn more about ideal gas law equation, here:

https://brainly.com/question/11544185

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