For the elementary process $2 \text{NOCl}(g) \rightarrow \text{Cl}_2(g) + 2 \text{NO}(g)$, the activation energy ($E_a$) and overall $\Delta E$ are 97.8 kJ/mol and 74.5 kJ/mol, respectively.

What is the activation energy for the reverse reaction?

The activation energy for the reverse reaction of the process 2NOCl(g) to Cl₂(g) + 2NO(g) is calculated to be 23.3 kJ/mol, which is found by subtracting the overall change in energy (74.5 kJ/mol) from the activation energy of the forward reaction (97.8 kJ/mol).

To find the activation energy for the reverse reaction, we can use the concept that the difference in activation energy between the forward and reverse reactions is equal to the overall change in energy (((G) of the reaction. In this case, the activation energy for the forward reaction (Ea forward) is given as 97.8 kJ/mol, and the overall change in energy (ΔE) is 74.5 kJ/mol. Therefore, to calculate the activation energy for the reverse reaction (Ea reverse), you subtract ΔE from Ea forward:

Ea reverse = Ea forward - ((G)

Ea reverse = 97.8 kJ/mol - 74.5 kJ/mol = 23.3 kJ/mol

The activation energy for the reverse reaction of the process 2NOCl(g) → Cl₂(g) + 2NO(g) is 23.3 kJ/mol.

For the elementary process \(2 \text{NOCl}(g) \rightarrow \text{Cl}_2(g) + 2 \text{NO}(g)\), the activation energy (\(E_a\)) and overall \(\Delta E\) are 97.8 kJ/mol and 74.5 kJ/mol, respectively.What is the activation energy for the reverse reaction?

Answer :

Other Questions

For the elementary process \(2 \text{NOCl}(g) \rightarrow \text{Cl}_2(g) + 2 \text{NO}(g)\), the activation energy (\(E_a\)) and overall \(\Delta E\) are 97.8 kJ/mol and 74.5 kJ/mol, respectively.

What is the activation energy for the reverse reaction?