High School

3.00 L of a solution contains 36.9 ppm of SnCl2.

A) 1.11 mg
B) 110.7 mg
C) 3.69 mg
D) 36.9 mg

Answer :

Final answer:

The mass of SnCl2 in the given solution is 1.11 mg.

Explanation:

To calculate the mass of SnCl2 in the given solution, we need to first convert the concentration from ppm to mg/L. ppm stands for parts per million, which means there are 36.9 mg of SnCl2 for every 1 million mg of solution. Convert 1 million mg to 1 L by multiplying by 1000 (since 1 L = 1000 mL) and divide by 3 (since we have 3 L of solution). This gives us 1,100 mg/L, which is equivalent to 1.11 grams per L. Therefore, the answer is (A) 1.11 mg.

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