Answer :
The specific heat capacity of tin, as measured by the student, is approximately 0.215 J/g·°C.The specific heat capacity of a substance is the amount of heat energy required to raise the temperature of a given mass of the substance by 1 degree Celsius (or 1 Kelvin).
In this case, the student has measured that it takes 39.3 J of heat energy to increase the temperature of 13.4 g of solid tin from 21.9 to 36.7 degrees Celsius.
To calculate the specific heat capacity of tin, we can use the formula:
q = m * c * ΔT
where:
q = heat energy (in joules)
m = mass of the substance (in grams)
c = specific heat capacity (in J/g·°C)
ΔT = change in temperature (in degrees Celsius or Kelvin)
In this case, we know the values of q (39.3 J), m (13.4 g), and ΔT (36.7 - 21.9 = 14.8 °C).
Let's substitute these values into the formula and solve for c:
39.3 J = 13.4 g * c * 14.8 °C
Divide both sides of the equation by (13.4 g * 14.8 °C) to solve for c:
c = 39.3 J / (13.4 g * 14.8 °C)
Calculating this gives us the specific heat capacity of tin:
c ≈ 0.215 J/g·°C
Therefore, the specific heat capacity of tin, as measured by the student, is approximately 0.215 J/g·°C.
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