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Given that the specific heat of chromium is 0.455 J/g∙K, find the final temperature after 35.9 J of energy is removed from 11.7 g of chromium initially at 28.5°C.

Answer :

Final answer:

The final temperature of the chromium after removing energy can be calculated using the specific heat equation. Plugging in the given values and solving for ∆T, the change in temperature, we find it to be -7.847K. Adding this change to the initial temperature of 28.5°C, we get a final temperature of 20.653°C.

Explanation:

The final temperature can be calculated using the specific heat formula:

Q = m * c * ∆T

Where:

Q is the energy transferred (given as -35.9J in this case)

m is the mass of the material (11.7g)

c is the specific heat capacity (0.455J/g∙K)

∆T is the change in temperature (to be calculated)

Plugging in the values and solving for ∆T:

(-35.9J) = (11.7g) * (0.455J/g∙K) * ∆T

∆T = (-35.9J) / (11.7g * 0.455J/g∙K)

∆T = -7.847K

Finally, to find the final temperature:

Final temperature = Initial temperature + ∆T = 28.5°C + (-7.847K) = 20.653°C

Answer:

[tex]T_2=35.2\°C[/tex]

Explanation:

Hello,

In this case, since the heat is computed in terms of mass, specific heat and temperature as follows:

[tex]Q=mCp(T_2-T_1)[/tex]

In such a way, for the given heat, we obtain the following temperature:

[tex]T_2=T_1+\frac{Q}{mCp}\\ \\T_2=28.5\°C+\frac{35.9J}{11.7g*0.455\frac{J}{g\°C} }\\ \\T_2=35.2\°C[/tex]

Best regards.

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