College

Consider the following observations on shear strength (MPa) of a joint bonded in a particular manner:

22.6, 40.4, 16.4, 72.4, 36.6, 109.8, 30.0, 4.4, 33.1, 66.7, 81.5

(a) What are the values of the fourths?

Answer :

Final answer:

To find the shear deformation of the disk between vertebrae in the spine, use the formula Δx = F(L₀)/(A(G)) and substitute the given values to calculate the deformation as 0.67 mm.

Explanation:

Shear deformation is calculated using the formula: Δx = F(L₀)/(A(G)), where Δx is shear deformation, F is the applied force, L₀ is the initial length, A is the area, and G is the shear modulus.

In this case, substituting the given values, we have: Δx = (600 N)(0.007 m)/((π(0.02 m²))(1x10^9 N/m²)) = 0.00067 m = 0.67 mm.

Therefore, the shear deformation of the disk between vertebrae in the spine subjected to a shearing force of 600 N is 0.67 mm.

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