Answer :
The volume of the hydrogen gas would decrease from 428 L to 339 L if 10.0 g of hydrogen gas is let out.
The relationship between the amount of gas and its volume is known as Avogadro's Law. This law states that at a constant temperature and pressure, the volume of a gas is directly proportional to the number of moles of gas. As a result, we may use the following formula: V1/V2 = n1/n2 Where V1 is the initial volume of the gas, V2 is the final volume of the gas, n1 is the initial quantity of the gas, and n2 is the final quantity of the gas.
According to the law, we may write: V1/n1 = V2/n2If 38.2 g of hydrogen gas has an initial volume of 428 L, the number of moles of hydrogen is calculated as n1 = 38.2/2 = 19.1 moles of hydrogen gas. When 10 g of hydrogen gas is released, the amount of hydrogen gas left would be (38.2 - 10) = 28.2 g. Thus, n2 = 28.2/2 = 14.1 moles of hydrogen gas. Substituting the values in the formula, we get: V1/n1 = V2/n2V1/(19.1) = V2/(14.1)V2 = V1 × (n2/n1)V2 = 428 × (14.1/19.1)V2 = 339 L.
Therefore, the volume of the hydrogen gas would decrease from 428 L to 339 L if 10.0 g of hydrogen gas is let out.
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