High School

As light shines from air into another medium, with an incident angle of [tex]$i = 30.0^\circ$[/tex], the light bends toward the normal and refracts at [tex]$22.0^\circ$[/tex]. What is the index of refraction?

A. 0.751
B. 1.33
C. 0.0262
D. 38.2

Answer :

To find the refractive index of a medium using Snell's Law, you can utilize the formula sin(i) / sin(r) = n₂ / n₁. In this scenario, the index of refraction for the second medium is 1.33, as calculated from given incident and refracted angles.

Therefore, the correct answer to the question is: b. 1.33

Index of refraction can be determined using Snell's Law, where n₁ is the index of refraction of air (usually taken as 1). Given an incident angle of 30.0° and a refracted angle of 22.0°, you can calculate the index of refraction for the second medium using the formula

  • sin(i) / sin(r) = n₂ / n₁.

The index of refraction for the second medium is 1.33. This value corresponds to option b in the provided choices.

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