College

Standard atmospheric pressure:
\[1 \text{ atm} = 101.3 \text{ kPa}\]

The gas in a sealed container has an absolute pressure of 125.4 kilopascals. If the air around the container is at a pressure of 99.8 kilopascals, what is the gauge pressure inside the container?

A. \[1.5 \text{ kPa}\]

B. \[24.1 \text{ kPa}\]

C. \[25.6 \text{ kPa}\]

D. \[112.6 \text{ kPa}\]

E. \[225.2 \text{ kPa}\]

Answer :

The gauge pressure inside the container is c) [tex]25.6 \text{ kPa}[/tex].

The formula we can use is:

[tex]P_g = P_{abs} - P_{atm}[/tex]

Where:

  • [tex]P_g[/tex] is the gauge pressure,
  • [tex]P_{abs}[/tex] is the absolute pressure of the gas,
  • [tex]P_{atm}[/tex] is the atmospheric pressure.

Given data:

  • [tex]P_{abs} = 125.4 \text{ kPa}[/tex]
  • [tex]P_{atm} = 99.8 \text{ kPa}[/tex]

Now we can plug these values into the formula:

[tex]P_g = 125.4 \text{ kPa} - 99.8 \text{ kPa}[/tex]

Calculating this gives us:

[tex]P_g = 125.4 - 99.8 = 25.6 \text{ kPa}[/tex]

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