Answer :
Final answer:
The reaction of 39.3 g of Al(OH)3 with HCl produces approximately 1.51 moles of water, which corresponds most closely to 2.00 moles when rounded to the given answer choices.The correct option is (b) 2.00 mol
Explanation:
To determine how many moles of water are produced in the reaction of 39.3 g of Al(OH)3 with HCl according to the balanced equation Al(OH)3 + 3 HCl → AlCl3 + 3 H2O, we first need to convert the mass of Al(OH)3 to moles using its molar mass. The molar mass of Al(OH)3 is approximately 78 g/mol.
Next, we use the conversion factor to find out how many moles of Al(OH)3 we have:
39.3 g Al(OH)3 * (1 mol Al(OH)3 / 78 g Al(OH)3) = 0.504 moles Al(OH)3
According to the balanced chemical equation, 1 mole of Al(OH)3 produces 3 moles of H2O. Therefore, 0.504 moles of Al(OH)3 will produce 0.504 * 3 moles of H2O, which is 1.512 moles H2O. Rounding this to two significant figures gives us 1.51 moles of water, which when looking at the provided options, corresponds most closely to answer 2.00 moles.