High School

Star A has a magnitude of 4 and Star B has a magnitude of 6. How much brighter is Star A than Star B?

a. 0.0006554
b. 0.16
c. 0.0002621
d. 1.5
e. 3.33
f. 1526
g. 0.0102
h. 2.5
i. 610
j. 97.7
k. 2
l. 0.00164
m. 5
n. 6.25
o. 3815

Answer :

The difference in magnitudes between the stars can be found using the formula Δm = m1 - m2. Where m1 = magnitude of star A, m2 = magnitude of star B, and Δm is the difference in magnitudes.

Given that Star A has a magnitude of 4 and Star B has a magnitude of 6. Therefore,Δm = 4 - 6= -2.

The negative sign indicates that star B is brighter than star A.

Thus, to find out how much brighter Star A is than Star B, we need to take the antilogarithm of Δm/2.5.

This can be calculated as follows:antilog (-2/2.5)= antilog (-0.8) = 0.1585.

The antilogarithm is approximately equal to 0.16.

Therefore, Star A is 0.16 times brighter than Star B. Answer: The brightness ratio between Star A and Star B is 0.16.

Learn more about stars here ;

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