Answer :
According to Gay-Lussac's law, the temperature of the fire at 39.3 atmospheres is 1350.82 Kelvin.
What is Gay-Lussac's law?
It is defined as a gas law which states that the pressure which is exerted by the gas directly varies with its temperature and at a constant volume.The law was proposed by Joseph Gay-Lussac in the year 1808.
The pressure of the gas at constant volume reduces constantly as it is cooled till it undergoes condensation .It is given as, P₁/T₁=P₂/T₂, thus T₂= 295.6×39.3/8.6=1350.82 kelvin
Thus, the temperature of the fire at 39.3 atmospheres is 1350.82 Kelvin.
Learn more about Gay-Lusac's law,here:
https://brainly.com/question/1358307
#SPJ1