High School

If 390 mL of nitrogen at 36.9 oC and 657 torr is

allowed to expand to 870 mL and 570 torr, what is the new

temperature in Celsius?

Answer :

Final answer:

The new temperature of nitrogen gas after expansion is approximately 726.9 oC.

Explanation:

To calculate the new temperature of nitrogen gas after expansion, we can use the equation (P1 * V1) / T1 = (P2 * V2) / T2, where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.

Given:

  • Initial volume (V1) = 390 mL
  • Initial temperature (T1) = 36.9 oC
  • Initial pressure (P1) = 657 torr
  • Final volume (V2) = 870 mL
  • Final pressure (P2) = 570 torr

First, we need to convert the temperatures to Kelvin. The Kelvin temperature scale is used in gas law calculations.

Initial temperature in Kelvin (T1) = 36.9 + 273.15 = 309.05 K

Using the equation, we can solve for the final temperature (T2):

(P1 * V1) / T1 = (P2 * V2) / T2

Substituting the given values:

(657 torr * 390 mL) / 309.05 K = (570 torr * 870 mL) / T2

Simplifying the equation:

255,630 torr * mL / K = 495,900 torr * mL / T2

Cross-multiplying:

255,630 torr * mL * T2 = 495,900 torr * mL * 309.05 K

Dividing both sides by 255,630 torr * mL:

T2 = (495,900 torr * mL * 309.05 K) / (255,630 torr * mL)

Canceling out the units:

T2 = 1,000.05 K

Finally, we need to convert the temperature back to Celsius:

T2 in Celsius = 1,000.05 K - 273.15 = 726.9 oC

Learn more about calculating the new temperature of nitrogen gas after expansion here:

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