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Miss Mae has three ribbons to be cut into equal lengths. The lengths of the ribbons are 24, 40, and 48 inches. What is the greatest possible length of each piece of ribbon to avoid leftover ribbons?

Answer :

4 if you write all the factors of 24, 40 and 48 the greatest common factor (GCF) it would be 4 :)

The greatest possible length of each piece of ribbon to avoid leftover ribbons will be 8 inches.

How to find the highest common factor?

Finding all common factors between two integers and choosing the biggest one yields the highest common factor (HCF).

​List every conceivable combination of the provided integers to get the highest common factor to answer word problems with that type of difficulty.

It is given that the lengths of the ribbons are 24. 40, and 48 inches as well as the three ribbons is to be cut into the same lengths.

The greatest possible length of each piece of ribbon to avoid leftover ribbons is obtained by calculating the highest common factor as,

24 - 1, 2, 3, 4, 6, 8, 12, 24

40 - 1, 2, 4, 5, 8, 10, 20, 40

48 - 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

The highest common factor for the three given lengths is 8 inches.

Thus, the greatest possible length of each piece of ribbon to avoid leftover ribbons will be 8 inches.

Learn more about the highest common factor here,

https://brainly.com/question/11467229

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