High School

A sample of oxygen was collected in a tube over water. In the tube, there is a mixture of oxygen gas and gaseous water (steam). The total pressure of the gas mixture is 760 torr. If the pressure of gaseous water is 23.8 torr, what is the pressure of the pure oxygen?

A. 99.8 torr
B. 736 torr
C. 740 torr
D. 783 torr

Answer :

Answer:

736 torr.

Explanation:

Final answer:

The pressure of the oxygen in the mixture can be found by subtracting the pressure of the gaseous water from the total pressure, according to Dalton's Law of Partial Pressures. This yields a pressure of 736.2 torr for the oxygen.

Explanation:

The total pressure inside the tube is the sum of the partial pressures of all the gases present. This is according to Dalton's Law of Partial Pressures, which states that the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of each individual gas. In this case, the total pressure of the mixture of oxygen and gaseous water (steam) is given as 760. torr. The pressure of the gaseous water (steam) is given as 23.8 torr.

To find the pressure of the oxygen, you can simply subtract the pressure of the gaseous water from the total pressure. This is referred to as the 'dry gas pressure', which is the pressure of the pure gas without the water vapor.

So, the pressure of the oxygen = Total pressure - Pressure of the gaseous water = 760 torr - 23.8 torr = 736.2 torr. However, considering the options, the closest value is 736 torr.

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