Answer :
Final answer:
The code snippet in question outputs the absolute value of -97.6 which is 97.6. A method with the signature String myMethod(String s, int i) is correctly represented by the option with a return type of double, and parameters String s, int i. The compareTo method outputs -1 when comparing 12 to 22, the Scanner nextLine method has a return type of string and no parameters. The correct code to generate random numbers between -10 and 10 is int n = (int) (Math.random() * 20) - 10.
Explanation:
The output of the code double x = -97.6; System.out.println(Math.abs(x)); will be A) 97.6 because the Math.abs method returns the absolute value of a given double value.
Among the described methods, the method that has the same signature as a method with return type of String, the name myMethod and a parameter list of String s, int i is B) return type: double, name: myMethod, parameter list: String s, int i
In the code segment Integer a = new Integer(12); Integer b = new Integer(22); System.out.println(a.compareTo (b));, the output will be B) -1. This is because the compareTo method compares two Integer values numerically and returns -1 if the first value is less than the second.
The method nextLine of the Scanner class has return type and parameters as described in option A) Return type: String. Parameters: none.
To generate random numbers between -10 and 10 inclusive, the correct code is D) int n = (int) (Math.random() * 20) - 10. This will produce a random number in the interval [-10,10].
Learn more about Java Programming here:
https://brainly.com/question/2266606
#SPJ11