High School

A race car entering the curved part of the track drops its speed from 45.1 m/s to 36.6 m/s in 2.99 seconds.

a) What is the acceleration?

b) What is the distance traveled?

c) What is the initial velocity?

d) What is the final velocity?

Answer :

Final answer:

The acceleration is -2.85 m/s², the distance traveled is 63.29 m, the initial velocity is 45.1 m/s, and final velocity is 36.6 m/s.

Explanation:

a) To find the acceleration, we can use the formula:

Acceleration = (Final Velocity - Initial Velocity) / Time

Plugging in the given values, we have:

Acceleration = (36.6 m/s - 45.1 m/s) / 2.99 s = -2.85 m/s²

b) To find the distance traveled, we can use the formula:

Distance = Initial Velocity * Time + (1/2) * Acceleration * Time²

Plugging in the given values, we have:

Distance = 45.1 m/s * 2.99 s + (1/2) * (-2.85 m/s²) * (2.99 s)² = 63.29 m

c) The initial velocity is given as 45.1 m/s.

d) The final velocity is given as 36.6 m/s.

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