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A pool is 33.7 m long and 36.6 m wide. If the average depth of water is 8.60 ft, what is the mass (in kg) of water in the pool? Enter your answer in scientific notation.


The density of water is 1.0 g/mL.


__ × 10 __ kg

Answer :

Final answer:

To find the mass of water in the pool, we multiply 33.7 m (length) by 36.6 m (width) by 2.62128 m (average depth) to get the volume of water. Then we multiply the volume by the density of water (1.0 g/mL) to convert it to kilograms, resulting in a mass of 2.60546825 × 10^7 kg.

Explanation:

To calculate the mass of water in the pool, we need to find the volume of water first. The volume of water can be found by multiplying the length, width, and average depth of the pool. Once we have the volume, we can convert it to kilograms by using the density of water.

Given:

  • Pool length = 33.7 m
  • Pool width = 36.6 m
  • Average depth of water = 8.60 ft
  • Density of water = 1.0 g/mL

First, convert the average depth of water from feet to meters: 8.60 ft * 0.3048 m/ft = 2.62128 m.

Now, calculate the volume of water: Volume = length * width * depth = 33.7 m * 36.6 m * 2.62128 m = 26054.6825 m³.

Finally, convert the volume to kilograms using the density of water: Mass = Volume * Density = 26054.6825 m³ * 1.0 g/mL * 1000 kg/m³ = 26054682.5 kg.

Therefore, the mass of water in the pool is 2.60546825 × 10^7 kg.

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