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In a Cartesian coordinate system (xyz), between the two points \( P_1 = (1 \, \text{cm}, 2 \, \text{cm}, 1 \, \text{cm}) \) and \( P_2 = (4 \, \text{cm}, 2 \, \text{cm}, 5 \, \text{cm}) \), there is an electric field directed along the line connecting \( P_1 \) to \( P_2 \) at any point. The magnitude of the electric field increases as \( 5s \), where \( s \) is the distance from point \( P_1 \).

Calculate the electric potential at a distance of 2 cm from point \( P_1 \), given that the electric potential at a distance of 4 cm from point \( P_1 \) is zero.

Select the result that is closest to your calculation:

A. -66.3 V
B. -75.1 V
C. +85.3 V
D. +97.8 V
E. 93.3 V
F. -83.5 V

Answer :

Answer:

(b) -75.1 v

Explanation:

The electrical potential at a point in an electrical field is related to the electrical field strength at that point and the distance from a reference point. If the electrical potential at a distance of 4 cm from Point P is zero, then we can use the given information to set up the following equation:

0 = 5 * 4^2 - V

Where V is the electrical potential at a distance of 2 cm from Point P. Solving for V, we get:

V = 20

The closest result to this value is option (b), 75.1 V. Therefore, the correct answer is (b).
Refer to the photo taken.

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