High School

A 6.75 g sample of gold (specific heat capacity = 0.130 J/g °C) is heated using 63.75 J of energy. If the original temperature of the gold is 25.0 °C, what is its final temperature?

A. 58.4 °C
B. 97.6 °C
C. 48.4 °C

Answer :

Answer:

b. 97.6 °C

Explanation:

Heat is the transfer of thermal energy that results in a change in temperature.

Heat Transfer

Heat is defined as the amount of energy that is transferred. So, if know the amount of energy used to heat a specific sample, then we can find the change in temperature. Additionally, since heat is being added to the sample, we know that the temperature will increase, not decrease.

Solving for Temperature

The equation that describes heat transfer is q = mcΔT. In this equation, q is energy, m is the mass of the sample, c is the specific heat capacity, and ΔT is the change in temperature. So, to find a change in temperature, we can plug in the information we were given.

  • 63.75 J = 6.75g * 0.130 J/g·°C * ΔT
  • 72.6 °C = ΔT

So, if we add the change in temperature to the initial temperature, we will get the final temperature.

  • 25.0 + 72.6 = 97.6

The final temperature of the gold is 97.6°C.

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