Answer :
The concentration of the original NaOH solution is 0.2636 M When 35.0 mL solution of NaOH is neutralized with 36.9 mL of 0.250 M HCL
To determine the concentration of the original NaOH solution, follow these steps:
1. Write the balanced chemical equation for the neutralization reaction:
[tex]NaOH + HCl[/tex] ⇒ [tex]NaCl + H_2O[/tex]
2. Calculate the moles of HCl used in the reaction:
Moles of HCl = volume (L) × concentration (M)
Moles of HCl = 36.9 mL × 0.250 M × (1 L/1000 mL)
Moles of HCl = 0.009225 mol
3. Determine the moles of NaOH in the reaction using the stoichiometry of the balanced equation (1:1 ratio):
Moles of NaOH = moles of HCl
Moles of NaOH = 0.009225 mol
4. Calculate the concentration of the NaOH solution:
Concentration (M) = moles/volume (L)
Concentration (M) = 0.009225 mol / (35.0 mL × 1 L/1000 mL)
Concentration (M) = 0.2636 M
Therefore , The concentration of the original NaOH solution is 0.2636 M.
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