Answer :
The pressure experienced by an object under the sea, like in this problem, can be associated with the principles of fluid mechanics, a key area of Physics.
In the ocean, the pressure increases linearly with depth due to the weight of the water above. This is described by the equation:
[tex]P = P_0 + \rho \cdot g \cdot h[/tex]
Where:
- [tex]P[/tex] is the pressure at depth.
- [tex]P_0[/tex] is the atmospheric pressure at the surface of the ocean (about 14.7 psi at sea level).
- [tex]\rho[/tex] is the density of the water (approximately 62.4 pounds per cubic foot for seawater).
- [tex]g[/tex] is the acceleration due to gravity (approximately 32.2 feet per second squared).
- [tex]h[/tex] is the depth in feet.
However, the problem statement indicates that the pressure at 50 feet is approximately 36.9 psi. This implies that the pressure due to the water portion alone (exclusive of atmospheric pressure) at that depth would be:[tex]P_{water} = 36.9 - 14.7 = 22.2 \, \text{psi}[/tex]
Given that you know the pressure at 50 feet is 36.9 psi and assuming the relationship is linear, you can construct a linear equation or relationship based to calculate pressures at other depths. Thus, if you need to find pressure at another depth, you could use proportionality from the known depth.