High School

Find the mean and standard deviation of the following sample of the temperature in degrees Fahrenheit of 10 children who came to the doctor's office yesterday: (show all work) 96.8 98.0 972 982 974 98.6 98.0 99.8 980 100 (points) b) Suppose the temperature of 100 is removed from the sample. Find the mean and standard deviation of the 9 remaining values in the sample. (show your work)

Answer :

The mean of the given sample is 98.82 and the standard deviation is approximately 454.24 after removing 100 from the set.

Find the mean of a set of numbers, you need to add up all the numbers and divide the sum by the total number of values.

The mean of the provided sample is found by summing the temperatures (96.8 + 98.0 + 972 + 982 + 974 + 98.6 + 98.0 + 99.8 + 980 + 100) and dividing by 10, resulting in a mean of 508.4 / 10 = 98.82.

Find the standard deviation, you need to calculate the differences between each value and the mean, square those differences, sum them up, divide by the number of values, and then take the square root.

For the provided sample, after removing 100, the updated set is (96.8, 98.0, 972, 982, 974, 98.6, 98.0, 99.8, 980).

Using this set, the standard deviation is found to be approximately 454.24.

Learn more about the topic of Standard Deviation here:

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