High School

A construction manager is monitoring the progress of the build of a new house. The scatterplot and table show the number of months since the start of the build and the percentage of the house still left to build. A linear function can be used to model this relationship.

New House

[tex]
\[
\begin{tabular}{|c|c|}
\hline
\text{Number of Months Since Start of Build, } x & \text{Percentage of House Left to Build, } y \\
\hline
0 & 100 \\
\hline
1 & 86 \\
\hline
2 & 65 \\
\hline
3 & 59 \\
\hline
4 & 41 \\
\hline
5 & 34 \\
\hline
\end{tabular}
\]
[/tex]

Which function best models the data?

A. [tex] y = -13.5x + 97.8 [/tex]

B. [tex] y = -13.5x + 7.3 [/tex]

C. [tex] y = 97.8x - 135 [/tex]

D. [tex] y = 7.3x - 97.8 [/tex]

Answer :

To find the function that best models the data, we can determine the equation of the line that best fits the given data points using a linear function. The data points are:

- Months ([tex]$x$[/tex]): 0, 1, 2, 3, 4, 5
- Percentage left to build ([tex]$y$[/tex]): 100, 86, 65, 59, 41, 34

The goal is to check each provided linear function to see which one best matches the pattern of this data.

Let's verify the options:

1. [tex]$y = -135x + 97.8$[/tex]
2. [tex]$y = -13.5x + 7.3$[/tex]
3. [tex]$y = 97.8x - 135$[/tex]
4. [tex]$y = 7.3x - 97.8$[/tex]

Through analysis, we determine the following:

1. Slope and Intercept:

- Calculating the slope and intercept through a fitting process, we find:

- Slope (rate of change): Approximately -13.46
- Intercept (initial value when [tex]$x=0$[/tex]): Approximately 97.81

2. Matching with Functions:

- Option 1: The slope (-135) and intercept (97.8) clearly do not match our findings.
- Option 2: The slope (-13.5) is close to -13.46, but the intercept (7.3) is far from 97.81.
- Option 3: The slope (97.8) and intercept (-135) do not match our determined values.
- Option 4: The slope (7.3) and intercept (-97.8) do not match our findings.

Based on our findings, none of the options perfectly matches the calculated slope and intercept values from the data. If we round the slope to -13.5 and the intercept to 97.8, Option 2 might appear close in its slope value but is incorrect for the intercept.

Thus, none of the provided functions exactly model the calculated slope and intercept from the data.

Other Questions