High School

A mixture of a solution is prepared by mixing equal quantity of moles of hexane and cyclohexane at 25oC. What is the total vapor pressure on the liquid? (Steam pr4esions at 25 oC of hexane and pure cyclohexane are 151.4 torr and 97.6 torr, respectively)

100 torr

249 torr

50 torr

124.5 torr

Answer :

The total vapor pressure of the mixture is 124.5 torr.

Given:

Vapor pressure of hexane (P_hexane) = 151.4 torr

Vapor pressure of cyclohexane (P_cyclohexane) = 97.6 torr

Since we are mixing equal quantities of moles of hexane and cyclohexane, the mole fraction of each component in the mixture is 0.5.

Using Raoult's law, the total vapor pressure of the mixture (P_total) is calculated as follows:

P_total = (mole fraction of hexane) * (vapor pressure of hexane) + (mole fraction of cyclohexane) * (vapor pressure of cyclohexane)

P_total = (0.5 * 151.4 torr) + (0.5 * 97.6 torr)

P_total = 75.7 torr + 48.8 torr

P_total = 124.5 torr

Therefore, the total vapor pressure of the mixture is 124.5 torr.

To know more about Raoult's law, visit:

https://brainly.com/question/2253962

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