Answer :
The pressure in the 5.00 L tank with 5.25 moles of oxygen at 39.3 °C is approximately 8.53 atm.
To determine the pressure in atm of a 5.00 L tank with 5.25 moles of oxygen at 39.3 °C, we can use the ideal gas law equation: PV = nRT.
Here, P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.0821 L⋅atm/mol⋅K), and T is the temperature in Kelvin.
Step 1: Convert the temperature from °C to Kelvin by adding 273.15 to 39.3 °C:
T = 39.3 + 273.15 = 312.45 K
Step 2: Plug the values into the ideal gas law equation:
P × 5.00 L = 5.25 moles × 0.0821 L⋅atm/mol⋅K × 312.45 K
Step 3: Solve for P:
P = (5.25 moles × 0.0821 L⋅atm/mol⋅K × 312.45 K) / 5.00 L
P ≈ 8.53 atm
So, the pressure in the 5.00 L tank with 5.25 moles of oxygen at 39.3 °C is approximately 8.53 atm.
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