College

The table below shows the height, [tex]h[/tex], in meters, of an object that is thrown off the top of a building as a function of [tex]t[/tex], the time in seconds after it is thrown.

[tex]\[

\begin{tabular}{|c|c|c|c|c|c|c|}

\hline

$t$ & 0.5 & 1 & 1.5 & 2 & 2.5 & 3 \\

\hline

$h$ & 70.125 & 81.8 & 91.025 & 97.8 & 102.125 & 104 \\

\hline

\end{tabular}

\][/tex]

Using your calculator to perform a quadratic regression, express the height of the object as a function of the number of seconds that have passed since the object was thrown. Round all numbers to one decimal place.

[tex]\square[/tex]

Answer :

Rounding all coefficients to one decimal place, the height of the object as a function of time (t) is h(t) = −4.9t²+ 33.4t + 46.0.

To find the quadratic regression equation for the given data, we can use the form:

h(t)=at²+bt+c

Using a quadratic regression calculator, we input the given data points:

(t = 0.5, h = 70.125)

(t = 1, h = 81.8)

(t = 1.5, h = 91.025)

(t = 2, h = 97.8)

(t = 2.5, h = 102.125)

(t = 3, h = 104)

After performing the quadratic regression, we get the following equation:

h(t) = −4.9t²+ 33.4t + 46.0. This equation models the height of the object over time after it is thrown.

Complete Question:

The table below shows the height, h, in meters, of an object that is thrown off the top of a building as a function of t, the time in seconds after it is thrown.

t 0.5 1 1.5 2 2.5 3

h 70.125 81.8 91.025 97.8 102.125 104

Using your calculator to perform a quadratic regression, express the height of the object as a function of the number of seconds that have passed since the object was thrown. Round all numbers to one decimal place.

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