High School

The distance between two locations, A and B, is calculated using a third location, C, at a distance of 15 miles from location B. If \(\angle B = 105^\circ\) and \(\angle C = 20^\circ\), what is the distance, to the nearest tenth of a mile, between locations A and B?

A) 42.4 miles
B) 35.9 miles
C) 6.3 miles
D) 5.3 miles

Answer :

First find ∠A: ∠A = 180°-(105°+20°) = 180°-125° = 55°
Make sure you know the Law of Sin (or Sin Law):
15/sin 55° = AB/sin 20°, then 15 / 0.81915 = AB/0.342
AB(0.81915) = 15(0.342)
AB(0.81915) = 5.13
AB = 5.13 : 0.81915 (ratio)
AB = 6.26 = 6.3 miles
Therefore, the distance between location A and location B is 6.3 miles.

The distance between the two locations A and B is option C, 6.3 miles.

What is Triangle?

A triangle is a two dimensional figure which consist of three vertices, three edges and three angles.

Sum of the interior angles of a triangle is 180 degrees.

We have,

for a triangle ABC,

∠B = 105° and ∠C = 20°

BC = 15 miles

We have the sine rule for a triangle ABC,

a / sin A = b / sin B = c / sin C

where a, b and c are the sides opposite to angles A, B and C respectively.

Here, by angle sum property,

∠A = 180° - (105° + 20°)

= 180° - 125°

= 55°

BC / sin A = AB / sin C

15 / sin (55°) = AB / sin (20°)

15 / 0.819 = AB / 0.342

AB = (15 / 0.819) × (0.342)

= 6.262 miles ≈ 6.3 miles

Hence the distance between locations A and B is 6.3 miles.

To learn more about Triangles, click on the link given below :

https://brainly.com/question/12460919

#SPJ2

Other Questions