Answer :
Final answer:
d) 97.7 grams
To create a 1.55 M glucose solution with 350.0 g of water, 97.7 grams of glucose are required, corresponding to option d).
Explanation:
To determine how many grams of glucose are needed to make a 1.55 M solution with 350.0 g of water, we first need to calculate the number of moles of glucose required. Molarity (M) is defined as moles of solute per liter of solution. Using the molarity formula M = moles of solute / liters of solution, we calculate:
Moles of glucose = 1.55 moles/L * 0.35 L = 0.5425 moles
Next, we use the molar mass of glucose (C6H12O6) which is 180.2 g/mol to find the mass of glucose required:
Mass of glucose = moles of glucose * molar mass of glucose = 0.5425 moles * 180.2 g/mol = 97.7 grams
Therefore, 97.7 grams of glucose are needed to make a 1.55 M solution when dissolved in 350.0 g of water, which corresponds to option d).