Answer :
Final answer:
Two lamps of different powers connected first in series and then in parallel to a 220 V supply will draw different currents. When in series, the combined current is approximately 1.36 Amps, while in parallel, lamp 1 draws around 0.455 Amps and lamp 2 draws approximately 0.909 Amps.
Explanation:
This question pertains to electric circuits and involves two lamps connected in different configurations to a main supply of 220 V. The formula used to solve this problem is P = IV, where P represents power, I represents current, and V represents voltage.
When the lamps are connected in series, the total power for the two lamps combined is the sum of their individual powers, 100 Watts + 200 Watts = 300 Watts. Since the total voltage remains 220 V, we can solve for the current I. Hence, I(series) = P/V = 300 Watts / 220 V ≈ 1.36 Amps.
Alternatively, when the lamps are connected in parallel, the voltage remains the same across both lamps (220 V). However, the current drawn for each lamp will be calculated independently using the same formula, P = IV. Thus, I(lamp 1) = P/V = 100 Watts / 220 V ≈ 0.455 Amps for the first lamp and I(lamp 2) = 200 Watts / 220 V ≈ 0.909 Amps for the second lamp.
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