High School

Use the Remainder Theorem to find the remainder when [tex]f(x) = 3x^3 + 2x^2 - 3x + 8[/tex] is divided by [tex]x + 4[/tex].

A. [tex]f(-4) = -204[/tex]
B. [tex]f(-4) = -140[/tex]
C. [tex]f(0) = 8[/tex]
D. [tex]f(4) = 220[/tex]

Answer :

To find the remainder when [tex]\( f(x) = 3x^3 + 2x^2 - 3x + 8 \)[/tex] is divided by [tex]\( x + 4 \)[/tex], we can use the Remainder Theorem. The Remainder Theorem states that the remainder of the division of a polynomial [tex]\( f(x) \)[/tex] by a linear divisor [tex]\( x - c \)[/tex] is [tex]\( f(c) \)[/tex].

In this case, our divisor is [tex]\( x + 4 \)[/tex], which can be written as [tex]\( x - (-4) \)[/tex]. According to the Remainder Theorem, the remainder is [tex]\( f(-4) \)[/tex].

Let's evaluate [tex]\( f(-4) \)[/tex]:

1. Substitute [tex]\(-4\)[/tex] into the polynomial:

[tex]\[
f(-4) = 3(-4)^3 + 2(-4)^2 - 3(-4) + 8
\][/tex]

2. Calculate each term:

- [tex]\(3(-4)^3 = 3 \times (-64) = -192\)[/tex]
- [tex]\(2(-4)^2 = 2 \times 16 = 32\)[/tex]
- [tex]\(-3(-4) = 12\)[/tex]
- The constant term is [tex]\(8\)[/tex].

3. Add these values together:

[tex]\[
f(-4) = -192 + 32 + 12 + 8
\][/tex]

4. Simplify the expression:

[tex]\[
-192 + 32 = -160
\][/tex]
[tex]\[
-160 + 12 = -148
\][/tex]
[tex]\[
-148 + 8 = -140
\][/tex]

So, the remainder when [tex]\( f(x) \)[/tex] is divided by [tex]\( x + 4 \)[/tex] is [tex]\(-140\)[/tex].

Therefore, the correct answer is [tex]\( \boxed{\text{(B) } f(-4) = -140} \)[/tex].

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